Sox’ Ramirez bunts into triple play in Indians’ 7-1 win

SHARE Sox’ Ramirez bunts into triple play in Indians’ 7-1 win

CLEVELAND — The Indians turned a triple play on the White Sox during the third inning of Cleveland’s 7-1 victory at Progressive Field on Sunday.

With A.J. Pierzynski on first and Carlos Quentin on second, Alexei Ramirez popped up a bunt down the first-base line. Indians first baseman Carlos Santana came in and made a diving catch on the line.

Quentin was standing on third and Pierzynski on second. Both were easily out.

It was the Indians’ first triple play since 2008.

“The game changed with the bunt,” Sox manager Ozzie Guillen said. “If we put the ball down on the bunt, maybe it’s a different game.”

The Sox (2-1) trailed the Indians 2-1 on Orlando Cabrera’s two-run homer in the sixth against Sox starter John Danks, who struck out six and allowed one hit in the first three innings. Cabrera homered with two outs and hit the first pitch.

The Indians tacked on runs against the Sox bullpen, including Will Ohman, Phil Humber and Matt Thornton.

The last triple play the Sox hit into was on April 22, 1978 at Toronto.

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