The 33rd annual Maui Invitational announced its 2017 tournament bracket Tuesday.
The top half of the bracket showcases matchups between Marquette and VCU, and Wichita State and California. The bottom half has Notre Dame facing Chaminade and Michigan taking on LSU.
The bracket is set up to have a winning and losing route, and each team will play three games.
Here’s the full bracket of the tournament:
This will be the first time the Irish will play a Division II school in 16 seasons. Chaminade, the host school, and Notre Dame played once in 1993 at the tournament. The Irish won 94-78, and the teams haven’t played since.
If history repeats itself, and Notre Dame wins its opening game, which is Nov. 20 at 9 p.m., the Irish would face the winner of the Michigan-LSU game.
As for Marquette, the Golden Eagles will face the Rams on Nov. 20 at 2:30 p.m. Marquette and VCU suffered first-round exits during March Madness last season. The winner will face the winner of the Wichita State-California game on Nov. 21 at 1:30 p.m., and the losers will play each other Nov. 21 at 4 p.m.
The Maui Invitational started in 1984. The idea for the tournament, however, was sparked two years before when Chaminade beat then-No. 1-ranked Virginia in December 1982.
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